# Preparing Hydrochloric Acid Solution

## Question:

How much water would you add to 175 ml of 6.00 M hydrochloric acid to prepare a 2.00 M solution of this acid?

A. 350 ml

B. 700 ml

C. 58.3 ml

D. 525 ml

E. None of the above

## Answer:

350 ml

In order to prepare a 2.00 M solution of hydrochloric acid from a 6.00 M stock solution, we need to use the dilution equation formula, which is c1v1 = c2v2. Here, c1 represents the concentration of the stock solution, v1 represents the volume of the stock solution, c2 represents the concentration of the required solution, and v2 represents the volume of the required solution.

Given:

Concentration of stock solution of HCl = 6.00 M

Volume of stock solution of HCl = 175 mL

Concentration of required solution = 2.00 M

To find the total volume of the required solution, we substitute the values into the formula:

6.00 M x 175 mL = 2.00 M x V

V = 525 mL

Therefore, the final volume of the diluted solution is 525 mL. Since we already have 175 mL of acid, the volume of water to be added is:

525 mL - 175 mL = 350 mL

So, 350 mL of water should be added to prepare the 2.00 M hydrochloric acid solution.