# The Calculation of Resistance in Light Bulbs Connected in Series

## Understanding the Relationship Between Current, Voltage, and Resistance

When two identical light bulbs are connected in series, the current flowing through both bulbs is the same. In this case, the current is measured at 0.25 A. Additionally, the total voltage across both bulbs is 110 V.

## Determining the Resistance of a Single Light Bulb

To calculate the resistance of a single light bulb in the series circuit, we can use Ohm's Law formula: **I = V / R**

Given that the current **I** is 0.25 A and the voltage **V** is 110 V, we can substitute these values into the formula to find the resistance **R**.

**Answer:**

220 ohms

**Explanation:**

Using Ohm's Law formula: **I = V / R**

Substitute the given values: 0.25 = 110 / R

Solve for **R**: R = 110 / 0.25 = 440 ohms

The equivalent resistance of two bulbs in series is 440 ohms.

To find the resistance of a single light bulb, divide the equivalent resistance by the number of bulbs:

Resistance of single light bulb = Equivalent resistance / number of bulbs

= 440 / 2 = 220 ohms

What is the relationship between current, voltage, and resistance in a series circuit with two identical light bulbs? In a series circuit with two identical light bulbs, the current remains constant throughout the circuit. The voltage is divided across both bulbs, leading to a lower voltage drop across each individual bulb. The resistance of a single light bulb can be calculated by dividing the equivalent resistance of the circuit by the number of bulbs.